a car is traveling on a straight road at 19 m/s. the driver sees a bird standing in the road 38 meters ahead and applies the brakes, giving constant deceleration of 5 m/s2.
how far away is the driver from the bird when he stops( assuming the bird doesn't move)
"v=0" m/s , when he stops
"v_0=19" m/s, initial velocity
"a=-5" m/s"^2" , constant deceleration
"\\Delta x=\\frac{v^2-v_0^2}{2a}=\\frac{0^2-19^2}{2\\cdot (-5)}=36.1" m
"38-36.1=1.9" m
Answer: "1.9" m from the bird.
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