Question

The door of a five star hotel consists of four rectangular glass panels measuring 1.0 m by 2.5 m equally mounted on a rotating rod.Find the moment of inertia of the door with respect to this rod.Consider the dimensions of the rod as negligible compared to the dimensions of the glass panel.

Answer 1

$I=\frac 1{12} m(a^2+b^2),$

$I=0.6m~~~kg\cdot m^2.$