a)for Karen:
Pk=mkg−weight Karen
the beginning of the fall:
h0=0
v0=0
E=EP=0
end of fall:
h=−2.1m
Δx=−1.1m
h1=h+Δx=−3.2m
v1=0,hense EK=0
E=EPk+EPr=0
EPk−Karen’s potential energy
EPr -potential energy of the rope
EPk=mkgh1=−3.2mkg
EPr=−2FrΔx=0.55Fr
−3.2mkg+0.55Fr=0
Fr=5.82mkg=5.82Pk
Answer:
The force exerted by the rope is 5.82 times the weight
b) for Bill:
end of fall:
h=−2.1m
Δx′=45cm=0.45m
h1′=h+Δx′=−2.55m
EPb=mbgh1′=−2.55mbg
EPr′=−2Fr′Δx′=0.225Fr
−2.55mbg+0.225Fr′=0
Fr′=11.33mbg=11.33Pb
Answer:
The force exerted by the rope is 11.33 times the weight
c)Fr=5.82Pk
Fr′=11.33Pb
ak=5.82g
ab=11.33
Bill’s acceleration is greater than Karen’s,getting injured is also greater.
Answer:Bill is more likely to get hurt
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