Question #269780

Two rock climbers, Bill and Karen, use safety ropes of similar length. Karen's rope is more elastic, called a dynamic rope by climbers. Bill has a static rope, not recommended for safety purposes in pro climbing.

a)Karen falls freely about 2.1 m

m and then the rope stops her over a distance of 1.1 m

m . Estimate how large a force (assume constant) she will feel from the rope. (Express the result in multiples of her weight.)

b)In a similar fall, Bill's rope stretches by only 45 cm

cm . How many times his weight will the rope pull on him?

c)Which climber is more likely to be hurt?


1
Expert's answer
2021-11-22T10:13:37-0500

a)for  Karen:a) \text{for \ Karen:}

Pk=mkgweight KarenP_k= m_kg-\text{weight Karen}

the beginning of the fall:\text {the beginning of the fall:}

h0=0h_0= 0

v0=0v_0 = 0

E=EP=0E =EP = 0

end of fall:\text{end of fall:}

h=2.1mh = -2.1m

Δx=1.1m\Delta x=-1.1m

h1=h+Δx=3.2mh_1 = h+\Delta x=-3.2m

v1=0,hense EK=0v_1=0,\text{hense }EK =0

E=EPk+EPr=0E = EP_k+EP_r =0

EPkKaren’s potential energyEP_k-\text{Karen's potential energy}

EPr -potential energy of the ropeEP_r\text{ -potential energy of the rope}

EPk=mkgh1=3.2mkgEP_k = m_kgh_1=-3.2m_kg

EPr=FrΔx2=0.55FrEP_r = -\frac{F_r \Delta x}{2}= 0.55F_r

3.2mkg+0.55Fr=0-3.2m_kg+0.55F_r= 0

Fr=5.82mkg=5.82PkF_r = 5.82m_kg=5.82P_k


Answer:\text{Answer:}

The force exerted by the rope is 5.82 times the weight\text{The force exerted by the rope is }5.82\text{ times the weight}

b) for  Bill:b)\text{ \text{for \ Bill:}}

end of fall:\text{end of fall:}

h=2.1mh= -2.1m

Δx=45cm=0.45m\Delta x'=45cm =0.45m

h1=h+Δx=2.55mh'_1 = h+\Delta x'=-2.55m

EPb=mbgh1=2.55mbgEP_b = m_bgh'_1=-2.55m_bg

EPr=FrΔx2=0.225FrEP'_r = -\frac{F'_r \Delta x'}{2}= 0.225F_r

2.55mbg+0.225Fr=0-2.55m_bg+0.225F'_r= 0

Fr=11.33mbg=11.33PbF'_r = 11.33m_bg=11.33P_b

Answer:\text{Answer:}

The force exerted by the rope is 11.33 times the weight\text{The force exerted by the rope is }11.33\text{ times the weight}

c)Fr=5.82Pkc)F_r =5.82P_k

Fr=11.33PbF'_r =11.33P_b

ak=5.82ga_k = 5.82g

ab=11.33a_b=11.33

Bill’s acceleration is greater than Karen’s,getting injured is also greater.\text{Bill's acceleration is greater than Karen's,}\newline \text{getting injured is also greater.}

Answer:Bill is more likely to get hurt\text{Answer:Bill is more likely to get hurt}



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