Answer to Question #269453 in Mechanics | Relativity for Thel

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The spring oscillates to the other end. The amplitude is 3.5m, k = 1.2, and angular frequency is = 4.3 . Solve the wave speed.

Answer 1

wave number: $k=1.2$

angular frequency: $\omega=4.3$

Wavelength:

$$\lambda=2\pi/k=5.2\text{ m}.$$

Frequency:

$$f=\omega/2\pi=4.3/2\pi=0.68\text{ Hz}.$$

wave speed = frequency x wavelength

$=0.68Hz × 5.2m = 3.536m/s$