A 20-kg child on a swing can make a maximum angle of 400 with respect to the vertical. What is the child’s maximum speed if the chains of the swing have a length of 4 m?
h=4−4⋅cos40°=0.94 (m)h=4-4\cdot\cos40°=0.94\ (m)h=4−4⋅cos40°=0.94 (m)
mgh=mv2/2→v=2gh=2⋅9.8⋅0.94=4.3 (m/s)mgh=mv^2/2\to v=\sqrt{2gh}=\sqrt{2\cdot9.8\cdot0.94}=4.3\ (m/s)mgh=mv2/2→v=2gh=2⋅9.8⋅0.94=4.3 (m/s)
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