Question #268481

A 2.5 kg block is on a 53 degree inclined plane for which μk = 0.25 and μs = 0.5. Find its acceleration and its orientation knowing that :


a) it is initially at rest.


b) it moves up the slope.


c) it moves down the slope.

1
Expert's answer
2021-11-19T10:51:16-0500

a)


a=9.8(sin530.5cos53)=4.9ms2a=9.8(\sin 53 -0.5\cos 53)=4.9\frac{m}{s^2}

b)

a=9.8(sin53+0.25cos53)=9.3ms2a=9.8(\sin 53 +0.25\cos 53)=9.3\frac{m}{s^2}

c)


a=9.8(sin530.25cos53)=6.4ms2a=9.8(\sin 53 -0.25\cos 53)=6.4\frac{m}{s^2}



Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS