Question #26746

A race car is moving at a constant speed of 5.9m/s in a clockwise direction on a circular track of radius 128m. What is in m/s^2 it's tangential velocity at that time?

Expert's answer

A race car is moving at a constant speed of 5.9m/s5.9\mathrm{m/s} in a clockwise direction on a circular track of radius 128m. What is in m/s^2 it's tangential velocity at that time?

The radius of a track is R=128[m]R = 128[m] therefore its length is


L=2πR=2π128[m]=256π804.25[m].L = 2\pi R = 2\pi \cdot 128[m] = 256\pi \approx 804.25[m].


As the linear speed of a car is V=5.9[m/s]V = 5.9[m/s] it takes


T=L/VT = L/V


to make a full circle. Therefore, the angular velocity of a car is


ω=1/T=V/L.\omega = 1/T = V/L.


So, tangential velocity of a car is


Vtan=Rω=RV/L=128[m]5.9[m/s]/(256π[m])0.939[m/s].V_{\text{tan}} = R \cdot \omega = R \cdot V/L = 128[m] \cdot 5.9[m/s] / (256\pi[m]) \approx 0.939[m/s].


P.S. The dimension of tangential velocity is [m/s][m/s], not [m/s2][m/s^2].

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