Question

The position of a point is given as a function of time by x= 4t − 6t + 2t− 1 , where x and t are expressed in meters and seconds. Determine the position, the velocity, and the acceleration of the particle when t= 2 s.

Answer 1

$$x(2)=-1\ m\\v(2)=26\frac{m}{s}\\a(2)=36\frac{m}{s^2}$$