A plane flying at 80 m/s is uniformly accelerated at the rate of 2.0 m/s2. What is
the distance it will travel during a 10 s interval after acceleration begins?
S=ut+12at2S=ut+\frac {1} {2} at^2S=ut+21at2
S=(80m/s)(10s)+12(2.0m/s2)(10s)2S=(80m/s) (10s)+\frac {1} {2} (2.0m/s^2) (10s)^2S=(80m/s)(10s)+21(2.0m/s2)(10s)2
S=900metres.S=900metres.S=900metres.
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