How far shall an object fall for it to have a velocity of 3.50 m/s? Neglect air resistance.
L=V22gL=\frac{V^2}{2g}L=2gV2 ; V=3.50m/s
L=3.5022×9.8=0.625mL=\frac{3.50^2}{2\times 9.8}=0.625mL=2×9.83.502=0.625m
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