A bangka (boat) starts from rest. After 10 seconds, the bangka has a speed of 40 km/h.
(a) Compute the bangka’s final velocity in units of m/s.
(b) Compute the bangka’s average acceleration.
v0=0ms t=10s v=40kmhv_0=0 \frac{m}{s} \space\space\space\space t = 10s \space\space\space\space v=40\frac{km}{h}v0=0sm t=10s v=40hkm
a) the final velocity is v=v=v= 40kmh=40∗518=1009=1119ms40\frac{km}{h} = 40 * \frac{5}{18}=\frac{100}{9}=11\frac{1}{9}\frac{m}{s}40hkm=40∗185=9100=1191sm
b) average acceleration a=v−vota = \large\frac{v-v_o}{t}a=tv−vo =1009∗110=109ms=119ms2=\frac{100}{9}*\frac{1}{10}=\frac{10}{9}\frac{m}{s}=1\frac{1}{9}\frac{m}{s^2}=9100∗101=910sm=191s2m
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