Explanations & Calculations
- Since gravitational acceleration is almost constant in low heights where most of the things happen you can use the 4 equations of motion appropriately.
- The question is asking for the travelled distance until it attains the given velocity having given only the gravitational acceleration and the final velocity you can use "\\small v^2=u^2+2as".
- Then,
"\\qquad\\qquad\n\\begin{aligned}\n\\small h&=\\small \\frac{v^2-u^2}{2g}\\\\\n&=\\small \\frac{(5ms^{-2})^2-u^2}{2\\times9.8ms^{-2}}\n\n\\end{aligned}"
- If the object falls from rest (u=0) it falls through a distance "\\small h=1.3\\,m"
- If it has an initial velocity (u>0) then its velocity needs to be calculated accordingly using that equation.
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