Question #266234

At what velocity shall a dropped object fall a distance of 1.75 m? Neglect air resistance.


1
Expert's answer
2021-11-15T10:33:12-0500

H=vv02gH=\large\frac{v-v_0}{2g}\to vo=0v=2gH=2101.75=35=5.916ms6msv_o=0 \to v = \sqrt{2gH}=\sqrt{2*10*1.75}=\sqrt{35}=5.916 \frac{m}{s} \thickapprox 6 \frac{m}{s}


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