At what velocity shall a dropped object fall a distance of 1.75 m? Neglect air resistance.
H=v−v02g→H=\large\frac{v-v_0}{2g}\toH=2gv−v0→ vo=0→v=2gH=2∗10∗1.75=35=5.916ms≈6msv_o=0 \to v = \sqrt{2gH}=\sqrt{2*10*1.75}=\sqrt{35}=5.916 \frac{m}{s} \thickapprox 6 \frac{m}{s}vo=0→v=2gH=2∗10∗1.75=35=5.916sm≈6sm
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