A 10-kg metal ball is dropped from the top of a building 5.0 - m high. How long will it take this object to hit the ground? Neglect air resistance.
v0=0v_0 = 0v0=0
s=5ms = 5 ms=5m
g=9.81ms2g= 9.81\frac{m}{s^2}g=9.81s2m
s=v0t+gt22s = v_0t+\frac{gt^2}{2}s=v0t+2gt2
t=2sg=109.81≈1st = \sqrt{\frac{2s}{g}}= \sqrt{\frac{10}{9.81}}\approx1st=g2s=9.8110≈1s
Answer: 1s\text{Answer: }1sAnswer: 1s
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