An object of mass moves round a circle of radius 6 m if the if the period of motion is π calculate the force towards the centre
Assume that m=5 kgm=5\ kgm=5 kg . So, we have
F=mv2/r=mω2r=m(2πT)2r=m(2ππ)2r=F=mv^2/r=m\omega^2r=m(\frac{2\pi}{T})^2r=m(\frac{2\pi}{\pi})^2r=F=mv2/r=mω2r=m(T2π)2r=m(π2π)2r=
=4mr=4⋅5⋅6=120 (N)=4mr=4\cdot5\cdot6=120\ (N)=4mr=4⋅5⋅6=120 (N) . Answer
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