A 1,200 kg car ascends a road inclined at 200 to the horizontal at 25 km/h. Neglecting frictional opposition, estimate the power required to keep going at this speed.
power required to keep going:
P=mg⃗⋅v⃗=mgvsinα=1200⋅9.8⋅25sin20°/3.6=27932P=m\vec{g}\cdot \vec{v}=mgvsin\alpha=1200\cdot 9.8\cdot25sin20\degree/3.6=27932P=mg⋅v=mgvsinα=1200⋅9.8⋅25sin20°/3.6=27932 W
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