A 200 kg load is hung on a wire having a length of 4 m, cross-sectional area 1.2 x10-4 m2 , and Young‘s modulus 8 x 1010 N/m2 . What is its increase in length?
m=200 kgL=4 mY=8×1010 N/m2A=1.2×10−4 m2Y=f/AΔL/LΔL=200×9.8×41.2×10−4×8×1010ΔL=0.816×10−3 mm=200 \; kg \\ L=4 \; m \\ Y = 8 \times 10^{10} \; N/m^2 \\ A = 1.2 \times 10^{-4} \; m^2 \\ Y = \frac{f/A}{ΔL/L} \\ ΔL = \frac{200 \times 9.8 \times 4}{1.2 \times 10^{-4} \times 8 \times 10^{10}} \\ ΔL = 0.816 \times 10^{-3} \; mm=200kgL=4mY=8×1010N/m2A=1.2×10−4m2Y=ΔL/Lf/AΔL=1.2×10−4×8×1010200×9.8×4ΔL=0.816×10−3m
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