Question #265061

A 200 kg load is hung on a wire having a length of 4 m, cross-sectional area 1.2 x10-4 m2 , and Young‘s modulus 8 x 1010 N/m2 . What is its increase in length?


1
Expert's answer
2021-11-15T13:04:58-0500

m=200  kgL=4  mY=8×1010  N/m2A=1.2×104  m2Y=f/AΔL/LΔL=200×9.8×41.2×104×8×1010ΔL=0.816×103  mm=200 \; kg \\ L=4 \; m \\ Y = 8 \times 10^{10} \; N/m^2 \\ A = 1.2 \times 10^{-4} \; m^2 \\ Y = \frac{f/A}{ΔL/L} \\ ΔL = \frac{200 \times 9.8 \times 4}{1.2 \times 10^{-4} \times 8 \times 10^{10}} \\ ΔL = 0.816 \times 10^{-3} \; m


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