Question #264968

A boy stands still in a weighing Machine which then read 65kg,he jumps upwards at the instant just before he jumps the machine reads 85kg.what acceleration does he acquire?


Expert's answer

ma=Nmgma=N-mg

where N=85gN=85g N


a=(Nmg)/m=(8565)/65=0.31a=(N-mg)/m=(85-65)/65=0.31 m/s2

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