A boy stands still in a weighing Machine which then read 65kg,he jumps upwards at the instant just before he jumps the machine reads 85kg.what acceleration does he acquire?
ma=N−mgma=N-mgma=N−mg
where N=85gN=85gN=85g N
a=(N−mg)/m=(85−65)/65=0.31a=(N-mg)/m=(85-65)/65=0.31a=(N−mg)/m=(85−65)/65=0.31 m/s2
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Finally I will be able to explain very well to the class in details
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Finally I will be able to explain very well to the class in details