a 71kg diver drops from a board 10m above the water surface. use conservation of mechanical energy to find his speed 5m above the water surface.
E0=P+K,E_0=P+K,E0=P+K,
E0=mgH,E_0=mgH,E0=mgH,
P=mgh,P=mgh,P=mgh,
K=mv22, ⟹ K=\frac{mv^2}2,\impliesK=2mv2,⟹
v=2g(H−h)=10 ms.v=\sqrt{2g(H-h)}=10~\frac ms.v=2g(H−h)=10 sm.
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