A cart is pushed ahead for 3.5 s with a force of 360 N. Determine the change in momentum of the cart. Show your work. You can take a photo of your notes.
The change in momentum of the cart is found by considering the force F acting on it for a time, "\\Delta t"
It is given that F =360N and "\\Delta t" =3.5s
The change in momentum of the cart is given by:
"\\Delta p = (F)(\\Delta t)"
"\\Delta p = (360)(3.5)"
"\\Delta p= 1260N.s"
Comments
Leave a comment