Question #263160

The area of no return at one intersection was calculated to be 59.0 m. What is the minimum length of time the traffic light should be yellow so a vehicle just entering the area of no return can clear the area while maintaining a speed of 70.0 km/h?


11.9 s


9.10 s


6.07 s


3.03 s


1
Expert's answer
2021-11-11T12:04:19-0500

v=70kmhv = 70\frac{km}{h}

s=59.0ms = 59.0m

v=701000360019.44msv =70* \frac{1000}{3600}\approx 19.44\frac{m}{s}

s=vts =v*t

t=sv=5919.443.03st = \frac{s}{v}= \frac{59}{19.44}\approx 3.03s


Answer: 3.03 s\text{Answer: }3.03\ s


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