A driver took 1.5 s to scan the instrument panel. During this time, the car was travelling at a speed of 105 km/h. The distance the car travelled while the driver scanned the panel was
s=vt,s=vt,s=vt,
s=1053.6⋅1.5=44 m.s=\frac{105}{3.6}\cdot 1.5=44~m.s=3.6105⋅1.5=44 m.
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