A force of 5 N to is required to compress an industrial spring by 0.0001 meters, how much force
is required to compress this spring by 0.0003 meters?
Explanations & Calculations
5F=k×0.0001k×0.0003F=15 N\qquad\qquad \begin{aligned} \small \frac{5}{F}&=\small \frac{k\times0.0001}{k\times0.0003}\\ \small F&=\small 15\,N \end{aligned}F5F=k×0.0003k×0.0001=15N
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