Express the rotational kinetic energy of the earth in terms of its period of rotation. The moment
of inertia of the earth about its spin axis is 8.04 × 1037 kg m2. Calculate its rotational kinetic
energy
1
Expert's answer
2013-03-13T04:32:46-0400
The rotational kinetic energy equals: Ec = I*w^2/2 I -moment of inertia w - angular speed In another side: w = 2*pi/T pi = 3.14 T - period Finally: Ec = I*(2*pi/T)^2/2 = 2*I(pi/T)^2 For the Earth -& T = 24 hours = 24*60 minutes = 24*60*60 seconds Ec = 2* 8.04 × 10^37 kg m2 * (3.14/(24*3600))^2 =& 2.13*10^29 J Answer: Ec = 2.13*10^29 J
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
Finding a professional expert in "partial differential equations" in the advanced level is difficult.
You can find this expert in "Assignmentexpert.com" with confidence.
Exceptional experts! I appreciate your help. God bless you!
Comments
Leave a comment