Question #262054

Find the Torque about the rotation produced by constant force of






(6 + 8 โˆ’ 10 ) ๐‘ on a particle situated at (3 โˆ’ 4 ) ๐‘š.

1
Expert's answer
2021-11-08T17:10:16-0500

Vectors given:


Fโƒ—=(6i+8jโˆ’10k),rโƒ—=(3iโˆ’4j+0k).\vec F=(6\textbf i+8\textbf j-10\textbf k),\\ \vec r=(3\textbf i-4\textbf j+0\textbf k).

Torque:


ฯ„โƒ—=Fโƒ—ร—rโƒ—,ฯ„=(8โ‹…0โˆ’(โˆ’10)โ‹…(โˆ’4), (โˆ’10)โ‹…3โˆ’6โ‹…0, 6โ‹…(โˆ’4)โˆ’8โ‹…3),ฯ„โƒ—=(โˆ’32,โˆ’30,โˆ’48) Nโ‹…m.\vec\tau=\vec F\times\vec r,\\ \tau=(8ยท0-(-10)ยท(-4),\space(-10)ยท3-6ยท0,\space6ยท(-4)-8ยท3),\\ \vec\tau=(-32,-30,-48)\text{ N}ยท\text m.


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