Question #262050

A 0.10 Kg model rocket’s engine is designed to deliver an impulse of 6.0 N·s. If


the rocket engine burns for 0.75 s, what is the average force does the engine


produce?

Expert's answer

m=0.1kgm = 0.1kg

Δt=0.75s\Delta t = 0.75s

J=6.0NsJ = 6.0N*s

J=mΔvJ = m\Delta v

Faverage=ma=mΔvΔtF_{average} =ma= m\frac{\Delta v}{\Delta t}

J=FaverageΔtJ= F_{average}\Delta t

Faverage=JΔt=60.75=8NF_{average}= \frac{J}{\Delta t}= {6}{0.75}= 8N


Answer: 8N\text{Answer: }8N



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