Question #262050

A 0.10 Kg model rocket’s engine is designed to deliver an impulse of 6.0 N·s. If


the rocket engine burns for 0.75 s, what is the average force does the engine


produce?

1
Expert's answer
2021-11-07T19:26:33-0500

m=0.1kgm = 0.1kg

Δt=0.75s\Delta t = 0.75s

J=6.0NsJ = 6.0N*s

J=mΔvJ = m\Delta v

Faverage=ma=mΔvΔtF_{average} =ma= m\frac{\Delta v}{\Delta t}

J=FaverageΔtJ= F_{average}\Delta t

Faverage=JΔt=60.75=8NF_{average}= \frac{J}{\Delta t}= {6}{0.75}= 8N


Answer: 8N\text{Answer: }8N



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