A 0.10 Kg model rocket’s engine is designed to deliver an impulse of 6.0 N·s. If
the rocket engine burns for 0.75 s, what is the average force does the engine
produce?
m=0.1kgm = 0.1kgm=0.1kg
Δt=0.75s\Delta t = 0.75sΔt=0.75s
J=6.0N∗sJ = 6.0N*sJ=6.0N∗s
J=mΔvJ = m\Delta vJ=mΔv
Faverage=ma=mΔvΔtF_{average} =ma= m\frac{\Delta v}{\Delta t}Faverage=ma=mΔtΔv
J=FaverageΔtJ= F_{average}\Delta tJ=FaverageΔt
Faverage=JΔt=60.75=8NF_{average}= \frac{J}{\Delta t}= {6}{0.75}= 8NFaverage=ΔtJ=60.75=8N
Answer: 8N\text{Answer: }8NAnswer: 8N
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