Answer to Question #261577 in Mechanics | Relativity for tamrat

Question

1.             A fish swimming in a horizontal plane has velocity v_i = (4.00i + 1.00j ) m/s at a point in the ocean where the position relative to a certain rock is r_i = (10.0i - 4.00j) m. After the fish swims with constant acceleration for 20.0 s, its velocity is v_f = (20.0i - 5.00j) m/s.

(a) What are the components of the acceleration?

(b) If the fish maintains constant acceleration, where is it at t =25.0 s?

Answer 1

a

b