A solid cylinder of wood has a cross sectional area of 20cm2 and height of 90cm. It floats upright in water. If two thirds of the length of the cylinder is submerged, calculate: the weight of the water displaced?
1
Expert's answer
2013-03-13T10:00:03-0400
According to the condition, volume of displaced waterequals 2/3 of cylinder's volume. We can easily find cylinder's volume: V=S*h, S - cross sectional area; h-height of the cylinderthen volume of displaced water is V1=2/3*S*h; The weight of the displaced water volume V1 is P=ρgV1, where ρ - density of water, g - gravitational acceleration. So, P=2/3*ρgSh; P=2/3*1000*10*20*10^(-4)*0.9=12 (N)
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Comments
Leave a comment