Question #261003

a 25 kg child sits in a swing that is attached to ropes 1.5 m long. It is 0.5m above the ground. Find the potential energy of the child relative to his lowest position when the ropes are (a) horizontal, (b) vertical ; (c) make 30 degrees with the horizontal.

1
Expert's answer
2021-11-08T09:12:32-0500

Explanations & Calculations


  • When the child is sitting on the swing at rest above the ground is when he experiences the lowest potential energy.
  • Any swing back and forth increases the potential energy.
  • When potential energy is measured relative to the child's lowest position, the net distance from that level need to be considered.


a)

  • When the ropes are horizontal, the vertical distance between the two locations is 1.5m.\small 1.5m.
  • Then the relative potential energy is

E1=mgΔh=25kg×9.8×1.5m=367.5J\qquad\qquad \begin{aligned} \small E_1&=\small mg\Delta h\\ &=\small 25kg\times9.8\times1.5m\\ &=\small 367.5\,J \end{aligned}

b)

  • the relative potential energy is 0.


c)

  • The hight difference at this location is

Δh=1.5(1sin30)=0.75m\qquad\qquad \begin{aligned} \small \Delta h&=\small 1.5(1-\sin30)=0.75m\\ \end{aligned}

  • Therefore, the relative potential energy is

E2=2.5×9.8×0.75=18.4J\qquad\qquad \begin{aligned} \small E_2&=\small 2.5\times9.8\times0.75\\ &=\small 18.4J \end{aligned}



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