Question #26013

an object start from rest with a constant acceleration 8 m/(s2 ) along a straight line find A- the speed at the end of 5 s B-the average speed for the 5s interval c-the distance traveled

Expert's answer

QUESTION:

An object start from rest with a constant acceleration 8m/(s2)8 \, \text{m/(s}^2) along a straight line find

A- the speed at the end of 5 s

B- the average speed for the 5s interval

C- the distance travelled

SOLUTION:

The velocity of the object is


v=v0+atv = v_0 + at


And, as at t=0t=0 object was in rest v0=0v_0 = 0, so


v=atv = at


And at the end of t1=5t_1=5 s velocity of the object is


v=at1=85=40m/sv = at_1 = 8 \cdot 5 = 40 \, \text{m/s}


The average speed is

v=st1\overline{v} = \frac{s}{t_1}, where s is the distance travelled by the object.


s=v0t1+at122s = v_0 t_1 + \frac{a t_1^2}{2}v0=0v_0 = 0s=at122s = \frac{a t_1^2}{2}s=8522=100ms = \frac{8 \cdot 5^2}{2} = 100 \, \text{m}


Hence, the average speed is


v=st1=1005=20m/s\overline{v} = \frac{s}{t_1} = \frac{100}{5} = 20 \, \text{m/s}


or, as at1=vat_1 = v, and v0=0v_0 = 0:


v=v2=402=20m/s\overline{v} = \frac{v}{2} = \frac{40}{2} = 20 \, \text{m/s}

ANSWER:

A) v=40m/sv = 40 \, \text{m/s}

B) v=20m/s\overline{v} = 20 \, \text{m/s}

C) s=100ms = 100 \, \text{m}

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