QUESTION:
An object start from rest with a constant acceleration 8m/(s2) along a straight line find
A- the speed at the end of 5 s
B- the average speed for the 5s interval
C- the distance travelled
SOLUTION:
The velocity of the object is
v=v0+at
And, as at t=0 object was in rest v0=0, so
v=at
And at the end of t1=5 s velocity of the object is
v=at1=8⋅5=40m/s
The average speed is
v=t1s, where s is the distance travelled by the object.
s=v0t1+2at12v0=0s=2at12s=28⋅52=100m
Hence, the average speed is
v=t1s=5100=20m/s
or, as at1=v, and v0=0:
v=2v=240=20m/sANSWER:
A) v=40m/s
B) v=20m/s
C) s=100m