Question #259952

A block of wood weigh 4newton is placed on a horizontal table .it is then pulled by means of a string if the tension in the string is 2.5newton calculate the coefficient of static friction



1
Expert's answer
2021-11-01T19:24:40-0400

T=2.5N\vec T = 2.5N

Fg=4N\vec F_g= 4N

Ffr=T=2.5N\vec{F_{fr}}=\vec{T}= 2.5N

N=Fg=4N\vec N = \vec F_g=4N

Ffr=μN\vec F_{fr}=\mu \vec N

μ=FfrN=2.54=0.625\mu = \frac{\vec F_{fr}}{\vec N}=\frac{2.5}{4}= 0.625


Answer: μ=0.625\text{Answer: }\mu = 0.625



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