Question #258438

Spring constant of 0.13Kn/M. Solve the stretched (x) by forces. F1= 52 N


1
Expert's answer
2021-10-31T18:13:23-0400
x=Fk=52/130=0.4 m.x=\frac{F}{k}=52/130=0.4\text{ m} .


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