Question #258101

1.For a body dropped from a height, h, the speed, V,with which it strikes the ground depends only on h

and g and a dimensionless numerical factor. Obtain an expression connecting v, h and g.


Expert's answer

a=ga=g

v=gt+v0v=gt+v_0


if v0=0v_0=0 :

v=gtv=gt


ht=h−gt2/2h_t=h-gt^2/2

where h is height at t=0,

ht is height at moment t


when body strikes the ground:

ht=0h_t=0

t=2hgt=\sqrt{\frac{2h}{g}}


speed, when body strikes the ground:


v=g2hg=2ghv=g\sqrt{\frac{2h}{g}}=\sqrt{2gh}


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