Question #258043
a car can go around a curve of radius 43 m at a speed of 12 m/s without skidding. what is the angle of banking?
1
Expert's answer
2021-10-29T11:32:02-0400

NsinθNcosθ=tanθ=mv2/rmg=v2gr\frac{Nsin\theta}{Ncos\theta}=tan\theta=\frac{mv^2/r}{mg}=\frac{v^2}{gr}


θ=arctanv2gr=arctan12m/s)2(9.81m/s2)(43m)=18.85\theta=arctan\frac{v^2}{gr}=arctan\frac{12m/s)^2}{(9.81m/s^2)(43m)} =18.85


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS