Question #257943

378 𝑙𝑝𝑠 of air is isothermally compressed at 27℃ and 1379 𝑘𝑃𝑎𝑎; 𝑝2 = 4136 𝑘𝑃𝑎𝑎. For both nonflow and steady-flow (𝑉1 = 23 𝑚 𝑠 , 𝑉2 = 46 𝑚 𝑠 , ∆𝑃 = 0) processes, compute (a) ∫ 𝑝𝑑𝑉 𝑎𝑛𝑑 − ∫ 𝑉𝑑𝑝 (b) ∆𝑈, ∆𝐻, 𝑎𝑛𝑑 ∆𝑆 (c) 𝑊 𝑎𝑛𝑑 𝑄 


1
Expert's answer
2021-11-01T12:54:50-0400

a)

pdV=νRT=572.5 kJ,\int pdV=\nu RT=572.5~kJ,

Vdp=p2V2p2V2=575.2 kJ,\int Vdp=p_2V_2-p_2V_2=-575.2~kJ,

b)

ΔU=pΔVVΔp=4.8 kJ,\Delta U=p\Delta V-V\Delta p=4.8~kJ,

ΔH=ΔU+pV=572.5 kJ,\Delta H=\Delta U+pV=572.5~kJ,

ΔS=UT=1.9085 kJK,\Delta S=\frac UT=1.9085~\frac{kJ}K,

c)

W=2ΔU=9.6 kJ,W=2\Delta U=9.6~kJ,

Q=pV=575.2 kJ.Q=pV=575.2~kJ.


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