Question #257943

378 š‘™š‘š‘  of air is isothermally compressed at 27ā„ƒ and 1379 š‘˜š‘ƒš‘Žš‘Ž; š‘2 = 4136 š‘˜š‘ƒš‘Žš‘Ž. For both nonflow and steady-flow (š‘‰1 = 23 š‘š š‘  , š‘‰2 = 46 š‘š š‘  , āˆ†š‘ƒ = 0) processes, compute (a) ∫ š‘š‘‘š‘‰ š‘Žš‘›š‘‘ āˆ’ ∫ š‘‰š‘‘š‘ (b) āˆ†š‘ˆ, āˆ†š», š‘Žš‘›š‘‘ āˆ†š‘† (c) š‘Š š‘Žš‘›š‘‘ š‘„ 


Expert's answer

a)

∫pdV=νRT=572.5 kJ,\int pdV=\nu RT=572.5~kJ,

∫Vdp=p2V2āˆ’p2V2=āˆ’575.2 kJ,\int Vdp=p_2V_2-p_2V_2=-575.2~kJ,

b)

Ī”U=pĪ”Vāˆ’VĪ”p=4.8 kJ,\Delta U=p\Delta V-V\Delta p=4.8~kJ,

Ī”H=Ī”U+pV=572.5 kJ,\Delta H=\Delta U+pV=572.5~kJ,

Ī”S=UT=1.9085 kJK,\Delta S=\frac UT=1.9085~\frac{kJ}K,

c)

W=2Ī”U=9.6 kJ,W=2\Delta U=9.6~kJ,

Q=pV=575.2 kJ.Q=pV=575.2~kJ.


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