Question #257661

Patrons on an amusement park ride called the Rotor stand with their backs against the wall of a rotating cylinder while the floor drops away beneath them. To keep from sliding downward, they require a centripetal acceleration in excess of about 25 ms^-2. The rotor has a diameter of 5.0 m. What is the minimum frequency for its rotation?

1
Expert's answer
2021-10-31T18:11:52-0400

Solution.

a=25m/s2;a=25 m/s^2;

d=5m;d=5m;

n?;n -?;

a=v2r    v=ar;a=\dfrac{v^2}{r}\implies v=\sqrt{ar};

v=252.5=62.5=7.9m/s;v=\sqrt{25\sdot2.5}=\sqrt{62.5}=7.9 m/s;

v=2πrn    n=v2πr;v=2\pi rn\implies n=\dfrac{v}{2\pi r};

n=7.923.142.5=0.5s1;n=\dfrac{7.9}{2\sdot 3.14\sdot2.5}=0.5s^{-1};


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