Question

My question is about Einstein light clock , could you please someone can explain.

On experiment clock moving in angle 90 degrees to the light ball direction between two mirrors , what if clock moves the same direction as a light ball moving?

Regards

Answer 1

We break the motion of the light up into two parts: the outgoing part (before reflection) and the returning part (after reflection).

outgoing time:

for the outgoing part the distance traveled by the light in time Δt'_o is

$c\Delta t_0'=l'+v\Delta t_0'$

The light travelled speed c for time $\Delta t_0'$. The light needed to move the length of the clock plus the amount the far end moved while the light was in transit. Anticipating the end result, rewrite this as

$c\Delta t_0'=\frac{l'}{1-v/c}$

returning time:

For the returning part the distance travelled by the light in time $\Delta t_0'$ is

$c\Delta t_r'=l'+v\Delta t_r'$

The light travelled speed c for time $\Delta t_r'$. The light needed to move This time the light needed to move less than the length of the clock, because the front of the clock moved towards the light while it was in transit. Or

$c\Delta t_r'=\frac{l'}{1+v/c}$