Explanations & Calculations.
75kmh−1=3600s75×1000m=20.8ms−1
- To calculate the maximum height it will reach, apply v2=u2+2as for its vertical motion. (in a projectile motion, an object has motion in both vertical & horizontal directions)
v202h=u2+2as=(20.8sin59ms−1)2+2(−9.8ms−2)×h=16.2m
- To calculate the time of flight, apply s=ut+21at2 for the projectile's vertical motion.
0mt∴t=(20.8sin59)t+0.5×(−9.8ms−2)t2=0sor3.6s=3.6s
- To calculate the horizontal distance, apply s=ut+21at2 to its horizontal motion.
- For the horizontal motion, the acceleration is zero this equation simplifies as follows and the calculations become easy.
→s=(20.8cos59ms−1)×3.6s=38.6m
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