Question #256459

 How fast is an object moving if it has a centripetal acceleration of 460.8 m/s

2

460.8 m/s2

 and turns around in a circle with a radius of 5 m

5 m


1
Expert's answer
2021-10-25T15:24:40-0400

The centripetal acceleration for uniform circular motion is given as follows:


a=v2Ra = \dfrac{v^2}{R}

where vv is the speed of the object (constant), R=5mR = 5m is the radius of the circle. Expressing vv and substituting a=460.8m/s2a = 460.8m/s^2, obtain:


v=aR=460.8m/s25m=48m/sv = \sqrt{aR} = \sqrt{460.8m/s^2\cdot 5m} = 48m/s

Answer. 48 m/s.


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