Question #256183

A large man sits on a four-legged chair with his feet off the floor. The combined mass of the man and chair is 95.0 kg. If the chair legs are circular and have a radius of 0.500 cm at the bottom, what pressure does each leg exert on the floor?


1
Expert's answer
2021-10-25T09:56:44-0400

P=FSP = \frac{F}{S}

m=95kgm = 95 kg

g=9.8ms2g = 9.8\frac{m}{s^2}

F=mg=959.8=931NF = mg = 95*9.8= 931N

r=0.5cm=0.5102mr = 0.5cm= 0.5*10^{-2}m

n=4n = 4

S=nπr2=4π0.25104=π104m2S = n\pi r^2= 4*\pi*0.25*10^{-4}= \pi*10^{-4}m^2

P=FS=931π1042.96106PaP = \frac{F}{S}= \frac{931}{\pi *10^{-4}}\approx2.96*10^6Pa


Answer: 2.96106 Pa\text{Answer: }2.96*10^6\ Pa


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