A large man sits on a four-legged chair with his feet off the floor. The combined mass of the man and chair is 95.0 kg. If the chair legs are circular and have a radius of 0.500 cm at the bottom, what pressure does each leg exert on the floor?
P=FSP = \frac{F}{S}P=SF
m=95kgm = 95 kgm=95kg
g=9.8ms2g = 9.8\frac{m}{s^2}g=9.8s2m
F=mg=95∗9.8=931NF = mg = 95*9.8= 931NF=mg=95∗9.8=931N
r=0.5cm=0.5∗10−2mr = 0.5cm= 0.5*10^{-2}mr=0.5cm=0.5∗10−2m
n=4n = 4n=4
S=nπr2=4∗π∗0.25∗10−4=π∗10−4m2S = n\pi r^2= 4*\pi*0.25*10^{-4}= \pi*10^{-4}m^2S=nπr2=4∗π∗0.25∗10−4=π∗10−4m2
P=FS=931π∗10−4≈2.96∗106PaP = \frac{F}{S}= \frac{931}{\pi *10^{-4}}\approx2.96*10^6PaP=SF=π∗10−4931≈2.96∗106Pa
Answer: 2.96∗106 Pa\text{Answer: }2.96*10^6\ PaAnswer: 2.96∗106 Pa
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