Question

A volleyball player serves a ball with his height of 1.5-meter height and

strikes the floor at point three meter horizontally.

a. Time of flight of the ball

b. Its horizontal velocity 

Answer 1

Let v be the horizontal velocity. Initial velocity in the vertical direction is zero.

(a) So, time to reach the ground is given by,

$h = \frac{1}{2}gt^2$

$t = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2 \times 1.5}{10}} = 0.55 s$

(b) Horizontal range is given by,

$x = vt$

$v = \frac{x}{t} = \frac{3}{0.55} = 5.45 m/s$