What downward force is exerted on a small piston with a radius of 2.0 cm would lift a 2000.0 kg car if the large piston has a radius of 12.0 cm?
for small piston:\text{for small piston:}for small piston:
r1=2cmr_1 = 2cmr1=2cm
S1=πr12=4π cm2S_1=\pi r_1^2= 4\pi \ cm^2S1=πr12=4π cm2
p1=F1S1p_1 =\frac{F_1}{S_1}p1=S1F1
for big piston:\text{\text{for big piston:}}for big piston:
g=9.81ms2g = 9.81\frac{m}{s^2}g=9.81s2m
m=2000kgm = 2000kgm=2000kg
F2=mg=2000∗9.81=19620NF_2= mg = 2000*9.81=19620NF2=mg=2000∗9.81=19620N
r2=12cmr_2=12cmr2=12cm
S2=πr22=144π cm2S_2= \pi r_2^2= 144\pi\ cm^2S2=πr22=144π cm2
p2=F2S2p_2 = \frac{F_2}{S_2}p2=S2F2
p1=p2p_1= p_2p1=p2
F1=S1F2S2=4π∗19620144π=545NF_1= S_1\frac{F_2}{S_2}=4\pi*\frac{19620}{144\pi}=545NF1=S1S2F2=4π∗144π19620=545N
Answer: 545N\text{Answer: }545NAnswer: 545N
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