Explanations & Calculations
- Equaling the torque of the total mass about the Y-axis to that of each individual mass, the x-distance to the centre of mass can be found.
(2+3+5)kg×XˉXˉ=5kg×3+3kg×2+2kg×(−3)=1.5
- Taking that about X axis,
(2+3+5)kg×YˉYˉ=2kg×(−1)+3kg×2+5kg×(−3)=−1.1
- Therefore, the centre of mass is located at (1.5,−1.1)
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