A 24-N horizontal force is applied to a 40-N block initially at rest on a rough horizontal
surface. If the coefficients of friction are µs = 0 .5 and µk = 0 .4, find the magnitude of the
frictional force on the block
Frictional force is
Ff=µk×mgFf = µk \times mgFf=µk×mg
Ff=µk×(F)Ff=0.4×(40)Ff=16mFf = µk \times (F) \\ Ff =0.4 \times (40) \\ Ff =16 mFf=µk×(F)Ff=0.4×(40)Ff=16m
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