Question #254458

A 24-N horizontal force is applied to a 40-N block initially at rest on a rough horizontal

surface. If the coefficients of friction are µs = 0 .5 and µk = 0 .4, find the magnitude of the

frictional force on the block


1
Expert's answer
2021-10-21T16:34:16-0400

Frictional force is

Ff=µk×mgFf = µk \times mg

Ff=µk×(F)Ff=0.4×(40)Ff=16mFf = µk \times (F) \\ Ff =0.4 \times (40) \\ Ff =16 m


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