Question #254377

A block of mass m1, placed on an inclined smooth plane is connected by a light string passing over a smooth pulley to mass m2, which moves vertically downwards. Find the tension in the string.


Expert's answer

Draw the free-body diagram:



Apply Newton's second law and assume the motion occurs at constant acceleration:


1:−m1a=−T+m1gcos⁡θ,2:T−m2g=−m2a. T=m2(g−a),−m1a=−m2g+m2a+m1gcos⁡θ,a(m2+m1)=m2g−m1gcos⁡θ, a=m2g−m1gcos⁡θm2+m1, T=m2(g−m2g−m1gcos⁡θm2+m1).1:-m_1a=-T+m_1g\cos\theta,\\ 2: T-m_2g=-m_2a.\\\space\\ T=m_2(g-a),\\ -m_1a=-m_2g+m_2a+m_1g\cos\theta,\\ a(m_2+m_1)=m_2g-m_1g\cos\theta,\\\space\\ a=\frac{m_2g-m_1g\cos\theta}{m_2+m_1},\\\space\\ T=m_2\bigg(g-\frac{m_2g-m_1g\cos\theta}{m_2+m_1}\bigg).


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