The gantry crane of Prob 2/105 is repeated here, and the tension in cable AB is 14kN. Replace this force as it acts on point A by an equivalent force couple system at O. Point B is located at the center of the container top.
F1=FABcos20+316+8+9+3=11.2 N,F_1=F_{AB}\cos \frac {20+3}{16+8+9+3}=11.2~N,F1=FABcos16+8+9+320+3=11.2 N,
F2=FABsin5+9+316+8+9+3=6.4 N.F_2=F_{AB}\sin\frac{5+9+3}{16+8+9+3}=6 .4~N.F2=FABsin16+8+9+35+9+3=6.4 N.
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