A ball is dropped from a window and hits the ground with a speed of 25 ft/s. How high above the ground is the window?
Given:
"v_0=25\\:\\rm ft\/s"
"g=32\\:\\rm ft\/s^2"
The maximum height
"h_{\\max}=\\frac{v_0^2}{2g}=\\frac{25^2}{2*32}=9.8\\:\\rm ft"
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