Question

A ball is dropped from a window and hits the ground with a speed of 25 ft/s. How high above the ground is the window?

Answer 1

Given:

$v_0=25\:\rm ft/s$

$g=32\:\rm ft/s^2$

The maximum height

$$h_{\max}=\frac{v_0^2}{2g}=\frac{25^2}{2*32}=9.8\:\rm ft$$