What is the volume of change of 2m3 of water at 20°C due to an applied pressure of 10 MPa?
ΔP=10MPa=107Pa\Delta P = 10MPa = 10^7PaΔP=10MPa=107Pa
V0=2m3V_0= 2m^3V0=2m3
K=2.2∗109Pa bulk modulus of elasticity of waterK = 2.2*10^9 Pa\text{ bulk modulus of elasticity of water}K=2.2∗109Pa bulk modulus of elasticity of water
K=−V0ΔPΔVK= -V_0\frac{\Delta P}{\Delta V}K=−V0ΔVΔP
ΔV=−V0ΔPK=−21072.2∗109=−0.91∗10−2m3\Delta V= -V_0\frac{\Delta P}{K}=-2\frac{10^7}{2.2*10^9}=-0.91*10^{-2}m^3ΔV=−V0KΔP=−22.2∗109107=−0.91∗10−2m3
Answer: the volume of water decreased by 0.91∗10−2m3\text{Answer: the volume of water decreased by }0.91*10^{-2}m^3Answer: the volume of water decreased by 0.91∗10−2m3
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