A person runs with an initial velocity of 5.0 m/s. Then he slows down at a constant rate of -1.2 m/s2 over a period of 3 seconds. What is his velocity at the end of time.
a=v2−v1t=1.2a=\frac{v_2-v_1}{t}=1.2a=tv2−v1=1.2 m/s2
v2=v1+at=5−1.2⋅3=1.4v_2=v_1+at=5-1.2\cdot 3=1.4v2=v1+at=5−1.2⋅3=1.4 m/s
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