A.
Angular speed ω=Translational speed vradius rω = \frac{Translational \; speed \; v}{ radius \; r}ω=radiusrTranslationalspeedv
thus ω=vr=6ms−10.09m=66.67 rad/sω = \frac{v}{r} = \frac{6 ms⁻¹}{0.09 m} = 66.67 \;rad/sω=rv=0.09m6ms−1=66.67rad/s
B.
As we know, length of thread that can be wound on spinning wheel in 3 s = translational speed×time=6×3=18mtranslational \; speed × time = 6×3=18 mtranslationalspeed×time=6×3=18m
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