Question #253019
lt is desired that the outer edge of a grinding wheel 9.0 cm in radius
moves at a rate of 6.Om/s. (a) Determine the angular speed of the
wheel. (b) What length of thread could be wound on the rim of the
wheel in 3.0 s when it is turning at this rate
1
Expert's answer
2021-10-18T10:55:46-0400

A.

Angular speed ω=Translational  speed  vradius  rω = \frac{Translational \; speed \; v}{ radius \; r}

thus ω=vr=6ms10.09m=66.67  rad/sω = \frac{v}{r} = \frac{6 ms⁻¹}{0.09 m} = 66.67 \;rad/s

B.

As we know, length of thread that can be wound on spinning wheel in 3 s = translational  speed×time=6×3=18mtranslational \; speed × time = 6×3=18 m


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